Chase Utley Biography, Age, Height, Weight, Family, Wiki & More
| BIRTHDAY | 17 December, 1978 |
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| BIRTH PLACE | Pasadena , California |
| COUNTRY | United States |
| AGE (2019) | 40 Years Old |
| BIRTH SIGN | Sagittarius |
| HEIGHT | in centimeters- 185 cm in meters- 1.85 m in Feet Inches- 6’ 0” |
| WEIGHT | in Kilograms- 91 kg in Pounds- 200.62 lbs |
Chase Utley Age, Birthday Facts and Birthday Countdown
40 years, 5 months, 8 days old age. Chase Utley will turn 41 on 17 December, 2019. Only 6 months, 21 days, 22 hours, 38 minutes has left for his next birthday.
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Birthdays Celebrated on Each Day of Week |
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Chase Utley has celebrated the total number of 40 birthdays till date. See the analysis by days count and bar graph. |
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Short Biography Edit
Chase Utley was born on 17-12-1978 in Pasadena in the state of California, United States. He is an American former Baseball Player.
Chase Utley Family, Relatives and Other Relations
He was born to Dave Utley and Terrell Utley. He has a sister named Taylor Ann Utley. He is married to Jennifer Utley since 2007 and has two children named Benjamin Cooper Utley and Maxwell Chase Utley.
