J. B. Smoove Biography, Age, Height, Weight, Family, Wiki & More


J. B. Smoove

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BIRTHDAY 16 December, 1965
BIRTH PLACE Plymouth , Washington , North Carolina
COUNTRY United States
AGE (2018) 52 Years Old
BIRTH SIGN Sagittarius
HEIGHT in centimeters- 193 cm
in meters- 1.93 m
in Feet Inches- 6’ 3”
WEIGHT in Kilograms- 90 kg
in Pounds- 198.42 lbs
Last Updated on : December 16, 2017

Other Name: Jerry Angelo Brooks, JB Smoove
Appearance: Hollywood

Birthday Countdown, Age and Birthday Facts & More

52 years, 11 months, 26 days old age. J. B. Smoove will turn 53 on 16 December, 2018. Only 3 days, 23 hours, 55 minutes has left for his next birthday.



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Birthdays Celebrated on Each Day of Week

J. B. Smoove has celebrated the total number of 52 birthdays till date. See the analysis by days count and bar graph.

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    52
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    13%
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  • 8
    15%
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  • 8
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Biography   Edit

J. B. Smoove was born on 16-12-1965 in Plymouth, Washington in the state of North Carolina, United States. He is an American Film Actor, Screenwriter, Comedian, Voice Artist, Philanthropist, Television Actor, Video Game Artist & Writer who known for his work in Hollywood industry.




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